Adding a series of numbers whose digits repeat, and each number increases one place value more than the number before it.

 

Ex.1  2+22+222+2222+22222=

Ex.2  5+55+555+5555=

Ex.3  1+11+111+…11111111=

Find how many elements are being added. Write from 1 to the number of elements as one number. For Ex.1, there are 5 elements making the number 12345.

Since the repeating digit is 2, multiply 2 times the number we just got to get the answer. For Ex.1, we have 2+22+222+2222+22222 = 2(12345) = 24690.

For Ex.2, the repeating number is 5 so we multiply it times 1234. We have 5+55+555+5555 = 5(1234) = 6170.

For Ex.3, the repeating number is 1 so we multiply it times 12345678. We have 1+11+111+1111=11111+111111+1111111+11111111 = 1(12345678) = 12345678.

 

This would have little use in mental speed math, but might be useful in some computations.

Author: David

I grew up near Clayton, AL and have lived over 30 years near Atlanta, GA. My interests include family, church, guitar, gardening, working with kids... and math! Life can be very interesting. My websites: chasingtrees.net mathshortcutblog.wordpress.com

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